13 lines
365 B
C++
13 lines
365 B
C++
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#include <iostream>
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using namespace std;
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int main() {
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int peaches = 1; // 第10天剩下的桃子数
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// 逆推从第10天到第1天
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for (int day = 9; day >= 1; --day) {
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peaches = (peaches + 1) * 2; // 每天的桃子数量是前一天的剩余加1再乘2
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}
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cout << "第1天摘的桃子数量是: " << peaches << endl;
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return 0;
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}
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