homework in 12.6

homework_1.cpp

@@ -0,0 +1,16 @@
+#include <iostream>
+using namespace std;
+
+int main() {
+    int n;
+    cin >> n;  // 输入一个正整数n
+    long long result = 1;  // 使用long long类型来避免结果溢出
+    
+    // 计算阶乘
+    for (int i = 1; i <= n; ++i) {
+        result *= i;
+    }
+
+    cout << result << endl;  // 输出阶乘的结果
+    return 0;
+}

homework_2.cpp

@@ -0,0 +1,12 @@
+#include <iostream>
+using namespace std;
+
+int main() {
+    int peaches = 1;  // 第10天剩下的桃子数
+    // 逆推从第10天到第1天
+    for (int day = 9; day >= 1; --day) {
+        peaches = (peaches + 1) * 2;  // 每天的桃子数量是前一天的剩余加1再乘2
+    }
+    cout << "第1天摘的桃子数量是: " << peaches << endl;
+    return 0;
+}

homework_laster.cpp

@@ -1,52 +0,0 @@
-#include<iostream>  //字母位移
-
-using namespace std;
-
-/*
-int main(){
-    char CIN,COUT;
-
-    cin >> CIN;
-
-    int CIN2 = CIN+=3;
-    
-    COUT = CIN2;
-
-    cout <<COUT;
-    return 0;
-}
-
-
-int main(){
-    while (true)
-    {
-        char letter;
-        int n = 3;
-
-        cin >>letter;
-        
-        if (letter >= 'A' && letter <= 'Z') {
-            char new_letter = (letter - 'A' + n) % 26 + 'A';
-            cout << new_letter<<endl;
-        }
-    }
-    
-    return 0;
-}*/
-
-int main(){
-    while (true)
-    {
-        char ch1,ch2;
-
-        int n = 3;
-
-        cin >>ch1;
-        ch2 = ((ch1 -65)+n) %26 +65;
-    
-        cout <<ch2<<endl;
-    }
-    
-    
-    return 0;
-}

old_homework/11.30.cpp

@@ -1,52 +0,0 @@
-#include<iostream>  //字母位移
-
-using namespace std;
-
-/*
-int main(){
-    char CIN,COUT;
-
-    cin >> CIN;
-
-    int CIN2 = CIN+=3;
-    
-    COUT = CIN2;
-
-    cout <<COUT;
-    return 0;
-}
-
-
-int main(){
-    while (true)
-    {
-        char letter;
-        int n = 3;
-
-        cin >>letter;
-        
-        if (letter >= 'A' && letter <= 'Z') {
-            char new_letter = (letter - 'A' + n) % 26 + 'A';
-            cout << new_letter<<endl;
-        }
-    }
-    
-    return 0;
-}*/
-
-int main(){
-    while (true)
-    {
-        char ch1,ch2;
-
-        int n = 3;
-
-        cin >>ch1;
-        ch2 = ((ch1 -65)+n) %26 +65;
-    
-        cout <<ch2<<endl;
-    }
-    
-    
-    return 0;
-}