//奇偶求和

#include<iostream>

using namespace std;

int main(){
    int n,sum1=0,sum2=0;
    cin >>n;

    for (int i = 1; i<=n; i+=2)
    {
        sum1+=i;
    }
    for (int i = 2; i <= n; i+=2)
    {
        sum2+=i;
    }
    cout <<sum1<<" "<<sum2<<endl;
    return 0;
}