21 lines
282 B
C++
21 lines
282 B
C++
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//奇偶求和
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#include<iostream>
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using namespace std;
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int main(){
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int n,sum1=0,sum2=0;
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cin >>n;
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for (int i = 1; i<=n; i+=2)
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{
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sum1+=i;
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}
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for (int i = 2; i <= n; i+=2)
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{
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sum2+=i;
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}
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cout <<sum1<<" "<<sum2<<endl;
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return 0;
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}
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