2024-12-27 23:05:21 +08:00
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#include <iostream>
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2024-12-21 10:09:35 +08:00
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using namespace std;
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2024-12-27 23:05:21 +08:00
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int main() {
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// 遍历1到200的所有数
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for (int i = 1; i <= 200; i++) {
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// 判断该数是否满足"3721"数的条件
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if (i % 3 == 2 && i % 7 == 1) {
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cout << i << " "; // 输出满足条件的数
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}
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2024-12-21 10:09:35 +08:00
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}
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return 0;
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2024-12-27 23:05:21 +08:00
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}
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